lad

Yeah, I wrote code and pressed get URL, but then I copied what was shown in the window

The clipboard content:

https://memory-graph.com/#code=+%23+What+is%2Bthe+output+of+this+Python+program%3F%0A+++%0Adef+fun%28a+%3D+%5B%5D%29%3A+%0A++++a+%2B%3D+%5B1%5D%0A++++return+a%0Afun%28%29+print%28fun%28%29%29

The window text:

The following URL has been copied to your clipboard with:

    The current code
    Set breakpoints
    Playback timestep
    Play/Pause state

https://memory-graph.com/#code=+%23+What+is+the+output+of+this+Python+program? +++ def+fun(a+=+[]):+ ++++a++=+[1] ++++return+a fun()+print(fun())

The latter doesn’t work, and I didn’t think of checking the former

There’s also a gotcha with default parameters:

def fun(a = []):
    a += [1]
    return a

fun()
print(fun()) # [1, 1]

To be fair, I had to read the linked question on SO to understand what was the possible alternative. I do expect that if I use += it is in place.

On the other hand with Python and Java I always keep forgetting if everything is by value or by reference, I really miss some extra clarity of the languages where you can see if something is mutable when passed to a function

I’d argue subscription is seen as very similar to micro transactions, although I can see that one is capped and other is not, so maybe subscription is less predatory